Difference between revisions of "MPLab 32bit Multiplication"
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| Line 47: | Line 47: | ||
CMP AL,'A' ;compares the value in the AL register (the character just read) with the character 'A'. | CMP AL,'A' ;compares the value in the AL register (the character just read) with the character 'A'. | ||
| − | JGE L5 | + | JGE L5 ; If the character in AL is greater than or equal to 'A', program jumps to Label L5. |
| − | SUB AL,30H | + | SUB AL,30H ; otherwise, it subtracts 30H from the ASCII value of the character, |
; converts a numeric character ('0' to '9') to its corresponding numerical value (0 to 9). | ; converts a numeric character ('0' to '9') to its corresponding numerical value (0 to 9). | ||
JMP L6 | JMP L6 | ||
Revision as of 00:45, 26 September 2023
32-bit Binary Multiplication
1. Define the model and architecture for the assembly code
.model small .stack 100H .386 ; specifies that the program will use instructions of the 80386 processor (32-bit instructions).
2. Define your data in the data section ( here you can define various data items: variables, constants, strings, arrays)
.data ; .data directive indicates the beginning of data section ; DATA1 and DATA2 are 32-bit variables initialized to 0. DATA1 dd 00000000H DATA2 dd 00000000H ; PROD1 and PROD2 32-bit uninitialized variables. PROD1 dd ? PROD2 dd ? ;define strings that will be displayed as messages to the user while executing the program. msg db 10,13,"Enter the First Number: $" msg1 db 10,13,"Enter the Second Number: $" msg2 db 10,13,"The Product (in Hexadecimal) is: $"
3. Define your instruction in the code section (here you write the assembly instructions that perform computations, control program flow, and interact with data variables and memory)
.code ; .code directive indicates the beginning of code section .startup ; the entry point of the program
; Using DOS interrupt 21H to display the message. MOV AH,09 MOV DX,OFFSET msg INT 21H
; Read the First Number and store it into DATA1
MOV EBX, 0 ;sets the value of the EBX register to zero
MOV CX, 8 ;sets the value of the CX register to 8
; Using Loop
AGAIN:
; Using DOS interrupt 21H to read a character
MOV AH, 01
INT 21H
CMP AL,'A' ;compares the value in the AL register (the character just read) with the character 'A'.
JGE L5 ; If the character in AL is greater than or equal to 'A', program jumps to Label L5.
SUB AL,30H ; otherwise, it subtracts 30H from the ASCII value of the character,
; converts a numeric character ('0' to '9') to its corresponding numerical value (0 to 9).
JMP L6
L5: SUB AL,37H
L6: SHL EBX,4
ADD BL,AL
LOOP AGAIN
MOV DATA1, EBX